Bottlehead Forum
General Category => General Discussion => Topic started by: adeep42 on March 08, 2017, 04:04:08 AM
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For another project I am working on, need to know what value resistor is required to bring 6 Volts dc down to 1.7Vdc-2.2Vdc.
Thanks in advance for help,
Alan
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You need to learn about Ohm's law to determine this. V=IR, so you have to know the current that will be going through the resistor to determine what the voltage drop will be across it.
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Thank you Doc. Found an Ohm's Law calculator on the web. Am I right that I need a 20 OHM resistor?
Thanks,
Alan
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You have not said what current (I) the circuit is drawing. You need that to use ohm's law. Not sure how you came up with 20 ohms for R.
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Found this calculator since.
http://www.ohmslawcalculator.com, then used their LED Resistor Calculator. Source voltage is 6Vdc, Voltage drop is 2 (LED requires 1.7-2.2V), current through LED is .25 ma (20-30ma per Parts-Express).
Using this calculator, resistor should be 160 Ohms.
Your thoughts and experience much appreciated,
Alan
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Voltage drop across the LED is 2V, but the voltage drop across the resistor is what you are concerned with. That would be 6Vsupply-2VLED=4Vresistor. To solve this without an online calculator, V/I=R=4V/.025A=160ohms.
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Thank you Doc.
Alan