Gain into 4 ohm?

Adrian · 2932

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Offline Adrian

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on: April 02, 2017, 12:13:33 PM
The product page says the gain is 8 into an 8 ohm load.
I assume this is with the output transformers connected for 8 ohms.

What would be the approximate gain if the outputs are connected for 4 ohms feeding 4 ohm speakers?

Adrian C.

VPI Prime w/Ortofon Quintet Black MC/Rothwell MCL Lundahl SUT/EROS/Submissive (3 output mod)/Mainline/Crack - Speedball/S.E.X. 2.1 - C4S/S.E.X. 3.0 - C4S/Paramounts - Blumenstein 2.2 Mini-Max w/DOF mod -Senn HD600/Viso HP50/Focal Elear.

Offline Paul Joppa

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Reply #1 on: April 02, 2017, 01:26:02 PM
The voltage gain would be about 0.7 times 8, or 5.6 - 0.7 being about the square root of 1/2.

Paul Joppa

Offline Adrian

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Reply #2 on: April 03, 2017, 03:06:31 PM
Got it:
assume power (watts) constant with v_1=8; R_1=8; R_2=4
w=v^2/R.
(V_1^2)/R_1 =(V_2^2)/R_2
v_2=v_1 √(R_2/R_1 )
v_2=8√(4/8)=5.66

(I think?)
« Last Edit: April 03, 2017, 03:10:46 PM by Adrian »

Adrian C.

VPI Prime w/Ortofon Quintet Black MC/Rothwell MCL Lundahl SUT/EROS/Submissive (3 output mod)/Mainline/Crack - Speedball/S.E.X. 2.1 - C4S/S.E.X. 3.0 - C4S/Paramounts - Blumenstein 2.2 Mini-Max w/DOF mod -Senn HD600/Viso HP50/Focal Elear.

Offline Rocketman248

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Reply #3 on: April 03, 2017, 04:47:46 PM
....I understood some of those words.  :o

Nick DeBrita
Yokosuka, Japan

Offline Paul Joppa

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Reply #4 on: April 03, 2017, 05:56:18 PM
Quote from: Adrian on April 03, 2017, 03:06:31 PM
Got it:
assume power (watts) constant with v_1=8; R_1=8; R_2=4
w=v^2/R.
(V_1^2)/R_1 =(V_2^2)/R_2
v_2=v_1 √(R_2/R_1 )
v_2=8√(4/8)=5.66

(I think?)
Looks like you got it!

Paul Joppa

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