First, if you haven't already run across this, it may help:
http://www.allaboutcircuits.com/vol_3/chpt_3/11.html
Second, as a practical matter, as usual Paul coincides pretty much with every thing I've ever heard about using Zeners: The Wattage rating is very generous in the real world, so de-rating it to about 20% or less of the stated rating is prudent.
Third, rather than give up on the idea, I would suggest devising a stack of zeners that gets you closer to your target output Voltage. You may not hit 283V exactly, but you should be able to get closer to your target. A stack of 5 56V zeners would give you 280V +or- tolerance, for instance. Then, size that first dropping resistor to consume most of the difference between your expected "raw" Voltage and your target Voltage. Not necessarily all, but certainly most.
After the zener stack, use a small cap to ground, like .1uF or smaller. Remember, at this point you shouldn't be needing any filtering or additional reservoir, you are concerned with bypassing whatever noise you suspect the zeners might produce. Feed this to your circuit without any additional resistance in series or filters in parallel.
The reason I recommend you persevere is that I have often found shunt regulators, where possible, to improve the sound of audio amps. This certainly seems like a case where one might be used.
Thanks for the link. I've read it a couple of times but I think there may be a "chicken and the egg" issue that I'm not understanding.
The link shows a battery source so the voltage is constant. On the other hand, I am using a transformer, so the voltage varies depending upon the current (not to mention the power company, etc. but I'm going to assume my power is fairly stable for this question).
???V ---+--2.5K--+ 280V
| Z
| Z
= Z
| Z
| Z
GND ---+--------+
So, if I take a swag based on values from PSUD using a current of 20mA and 40mA, then the rectified voltage will be between 340 and 380V. I'm not saying that the current going across the 2.5K resistor is 20 or 40mA, I'm just using those values as a way to guess what my starting voltage will be in PSUD.
Using the high value of 380V, then the 2.5K resistor will be dropping 100V with a current of 40mA (100/2500=0.04). Therefore the 2.5K resistor would need to be at least 4 watts (10 watts for safety).
Now, if my circuit is drawing 20mA, then there will be 20mA of current through the zener diodes, so they will be dissipating close to Paul's recommended 20% of their rating - 1.12W (56*0.02).
380V ---+--2.5K--+--280V--+
| Z |
| Z |
= Z 20mA 8 20mA
| Z |
| Z |
GND ---+--------+--------+
If the voltage is on the low side, then the 2.5K resistor will be dropping 60V with a current of 24mA. Will the diodes continue to regulate as long as the circuit doesn't draw more than 24mA? In other words, is there some minimum current that the diodes need to draw to work? How do I know this value?
Or... am I completely off? This is why I wish I could take a class on this stuff.
David B Bliss
Bottlehead: Foreplay I, Foreplay III, Paramour I w/Iron Upgrade, S.E.X. w/Iron Upgrade
Speakers: FE127E Metronomes, Jim Griffin Jordan/Aurum Cantus Monitors, ART Arrays
Other: Lightspeed Attenuator, "My Ref" Rev C Amps, Lampucera DAC