The load and resistors are in parallel, so they don't add as they do when they are in series. In essence, to get the equivalent parallel resistance, you need to take the invere of the sum of reciprocal values, which essentially means that the total will always be less than the smallest resistance in the series. Simple example would be two 10 ohm resistors: 1/10 + 1/10 = 2/10, inverted is 10/2, or 5. This is the same basic formula for n number of resistors, just add up all the reciprocals and then invert that number to get the equivalent resistance.
From this you can also see that very high resistances in on the order of several k, will have very little effect on the lowest resistance in the series, so the 2.xk resistors across the headphone jacks are negligible.
Hope this helps, I'm no teacher so I apologize for any assumptions I've made on your background.
-- Jim
« Last Edit: May 09, 2011, 05:13:27 AM by jrebman »
Jim Rebman -- recovering audiophile
Equitech balanced power; uRendu, USB processor -> Musette DAC -> 5670 tube buffer -> Finale Audio F138 FFX -> Cain and Cain Abbys near-field).
s.e.x. 2.1 under construction. Want list: Stereomour II
All ICs homemade (speaker and power next)