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Crack / Re: Bottlehead Crack Channel Imbalance Issue
« Last post by Paul Joppa on April 28, 2024, 12:35:51 PM »Well then, it's likely to be the 6080.
The attenuation of a pot is the ratio of two resistance measurements, wiper-to-ground divided by hot-to-ground. You seem to have measured wiper-to-hot. Assuming 7:30 is all the way off, then it represents hot-to-ground, so subtract your measurement from the 7:30 measurement to get wiper-to-ground, then divide that by the 7:30 value.
Example: left channel 9:00 measured 82.55K; subtract that from 86.2K to get 4.65K wiper-to-ground. Divide that by 86.2K to get 0.0423.
Do the same on the right channel to get 0.041.
Those are the attenuation factors at the 9:00 position. Comparing the two channels, the left is 4% louder at the 9:00 setting. I did the rest and got left 7% louder at 12:00, and 7% quieter at 2:00. That kind of variation is typical for ordinary pots.
The attenuation of a pot is the ratio of two resistance measurements, wiper-to-ground divided by hot-to-ground. You seem to have measured wiper-to-hot. Assuming 7:30 is all the way off, then it represents hot-to-ground, so subtract your measurement from the 7:30 measurement to get wiper-to-ground, then divide that by the 7:30 value.
Example: left channel 9:00 measured 82.55K; subtract that from 86.2K to get 4.65K wiper-to-ground. Divide that by 86.2K to get 0.0423.
Do the same on the right channel to get 0.041.
Those are the attenuation factors at the 9:00 position. Comparing the two channels, the left is 4% louder at the 9:00 setting. I did the rest and got left 7% louder at 12:00, and 7% quieter at 2:00. That kind of variation is typical for ordinary pots.