I'm planning to make a go of padding my input, but I want to make sure I'm not misunderstanding any of the above.
The simplest way of gaining some headroom, as I understand it, is to simply insert two resisters in the left and right channels of the signal path running in from the RCA jacks. So for example, I could disconnect the L and R wires from the input terminals of my pot, solder in one resister for each channel, attach the resisters to the the pot inputs, and call it a day? The other four terminals on the pot remain untouched, correct?
I'm working with a 100k TKD-2511 series pot and have a couple of Shinkoh tantalum 75k resisters on hand - so I think this is probably my best option in terms of giving my pot a little bit of extra headroom? [Presently, unless I digitally reduce the volume going into my dac (which I would like to avoid given that it means I'm no longer getting a bit-perfect data stream), I'm only able to turn my pot from 6:00 (zero volume) to 7:30 or so before my HD800's become uncomfortably loud.]
I'd really love to better understand the various "shunt mode" wiring options, but I'm finding myself fairly confused by the above-link (
http://www.siteswithstyle.com/VoltSecond/12_posistion_shunt/12_Position_Pure_Shunt.html ), largely due to the fact that it doesn't clearly show input and output terminals on the pot in the schematics. Here's a crop of the image I'm referring to:
(https://forum.bottlehead.com/proxy.php?request=http%3A%2F%2Fcdn.head-fi.org%2F9%2F9d%2F9d2dc935_Shuntmodes.JPG&hash=584df4027c66d91eb50b136a1193838ae5d58dab)
Is shunt mode "typical" where you essentially rewire the whole pot - as depicted in the picture below and discussed here:
http://www.world-designs.co.uk/forum/showthread.php?t=5795 ?
(https://forum.bottlehead.com/proxy.php?request=http%3A%2F%2Fhomepage.ntlworld.com%2Frichard.maile%2FWD%2FShuntMod2.gif&hash=d27a903ddd0253620d58f0bbb4a01b78a6ee1db7)
Alternatively, in shunt mode "easiest" - are you basically inserting resisters in the input path (as described above) and then bridging the input and output terminals of the pot with an additional wire, in each channel? I can't wrap my head around how this works, but it seems to be what the author is saying (as quoted below) in section 1.5 of
http://www.siteswithstyle.com/VoltSecond/12_posistion_shunt/12_Position_Pure_Shunt.html
1.5 The Easy Way to make the Stock Foreplay Volume Control into a Shunt Mode Volume Control:
1. Remove the wire connection from the top (right terminal) of the volume pot to the selector switch at the volume pot end.
2. Insert a resistor between the volume pot top (right terminal) and the loose wire going to the selector switch.
This resistor is typically 47.0K (3.3 dB minimum attenuation) to 200K (9.5 dB minimum attenuation) metal film when using a 100K volume pot.
3. Run a short wire from the wiper (middle terminal) to the top (right terminal) of the volume pot.
Am I understanding this correctly? The selector switch in the foreplay is simply the input right? Contrary to the above, Grainger's comment regarding using a resister as a bridge between the input and output terminals on the pot makes a lot more sense to me because this would at least give you parallel resistance. If you are placing the resisters in series with the input of the pot though, why would you then bridge the input and output terminals of the pot?
Thanks for any guidance you can offer me!