The cathode resistor dissipation is different (lower most often) than the plate dissipation.
We have 2.5V of bias under the cathode, and 3.6mA, Ohm's Law says Power=Volts*Amps, so we get 2.5V*0.0036A=0.009Watts.
From experience, a large safety margin is needed, so the cathode resistor should be rated to three times this power, or 0.027W. (So a 1/40th Watt or greater part is OK)
For the plate load resistor, we know we have 388V of raw B+, and 200V on the plate of the 12AT7. This is a difference of 188V. With a target current of 3.6mA through the tube, we have voltage and current, so we can solve for resistance.
V/I=R, or 188V/0.0036A=52,222 Ohms (47K-56K will probably work)
We also have V*A=P, or 188V*0.0036A=0.7W, so a 3W resistor would be nice here.
The gain of the Steremour will drop with this change, the distortion will go up (as you like), and potentially the noise floor as well. I don't think anybody has tried this, so if you do let us know what your observations are.
-PB